{"id":8119,"date":"2023-05-11T06:00:50","date_gmt":"2023-05-11T04:00:50","guid":{"rendered":"http:\/\/www.glc.us.es\/~jalonso\/exercitium\/?p=8119"},"modified":"2023-05-03T11:59:47","modified_gmt":"2023-05-03T09:59:47","slug":"11-may-23","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/11-may-23\/","title":{"rendered":"TAD de los polinomios: Divisibilidad de polinomios"},"content":{"rendered":"<p>Usando el <a href=\"https:\/\/bit.ly\/3KwqXYu\">tipo abstracto de los polinomios<\/a>, definir la funci\u00f3n<\/p>\n<pre lang=\"text\">\n   divisiblePol :: (Fractional a, Eq a) =>\n                   Polinomio a -> Polinomio a -> Bool\n<\/pre>\n<p>tal que <code>divisiblePol p q<\/code> se verifica si el polinomio <code>p<\/code> es divisible por el polinomio <code>q<\/code>. Por ejemplo,<\/p>\n<pre lang=\"text\">\n   \u03bb> pol1 = consPol 2 8 (consPol 1 14 (consPol 0 3 polCero))\n   \u03bb> pol1\n   8*x^2 + 14*x + 3\n   \u03bb> pol2 = consPol 1 2 (consPol 0 3 polCero)\n   \u03bb> pol2\n   2*x + 3\n   \u03bb> pol3 = consPol 2 6 (consPol 1 2 polCero)\n   \u03bb> pol3\n   6*x^2 + 2*x\n   \u03bb> divisiblePol pol1 pol2\n   True\n   \u03bb> divisiblePol pol1 pol3\n   False\n<\/pre>\n<p><b>Soluciones<\/b><\/p>\n<p>A continuaci\u00f3n se muestran las <a href=\"#haskell\">soluciones en Haskell<\/a> y las <a href=\"#python\">soluciones en Python<\/a>.<\/p>\n<p><a name=\"haskell\"><\/a><br \/>\n<b>Soluciones en Haskell<\/b><\/p>\n<pre lang=\"haskell\">\nimport TAD.Polinomio (Polinomio, polCero, consPol, esPolCero)\nimport Pol_Division_de_polinomios (resto)\n\ndivisiblePol :: (Fractional a, Eq a) =>\n                Polinomio a -> Polinomio a -> Bool\ndivisiblePol p q = esPolCero (resto p q)\n<\/pre>\n<p><a name=\"python\"><\/a><br \/>\n<b>Soluciones en Python<\/b><\/p>\n<pre lang=\"python\">\nfrom src.Pol_Division_de_polinomios import resto\nfrom src.TAD.Polinomio import Polinomio, consPol, esPolCero, polCero\n\n\ndef divisiblePol(p: Polinomio[float], q: Polinomio[float]) -> bool:\n    return esPolCero(resto(p, q))\n<\/pre>\n","protected":false},"excerpt":{"rendered":"<p>Usando el tipo abstracto de los polinomios, definir la funci\u00f3n divisiblePol :: (Fractional a, Eq a) => Polinomio a -> Polinomio a -> Bool tal que divisiblePol p q se verifica si el polinomio p es divisible por el polinomio q. Por ejemplo, \u03bb> pol1 = consPol 2 8 (consPol 1 14 (consPol 0 3&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"footnotes":"","_jetpack_memberships_contains_paid_content":false},"categories":[581],"tags":[265],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/8119"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/comments?post=8119"}],"version-history":[{"count":1,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/8119\/revisions"}],"predecessor-version":[{"id":8120,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/8119\/revisions\/8120"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/media?parent=8119"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/categories?post=8119"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/tags?post=8119"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}