{"id":7381,"date":"2022-09-21T06:00:54","date_gmt":"2022-09-21T04:00:54","guid":{"rendered":"http:\/\/www.glc.us.es\/~jalonso\/exercitium\/?p=7381"},"modified":"2022-09-02T16:02:31","modified_gmt":"2022-09-02T14:02:31","slug":"interseccion-conjuntista-de-listas","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/interseccion-conjuntista-de-listas\/","title":{"rendered":"Intersecci\u00f3n conjuntista de listas"},"content":{"rendered":"<p>Definir la funci\u00f3n<\/p>\n<pre lang=\"text\">\n   interseccion :: Eq a => [a] -> [a] -> [a]\n<\/pre>\n<p>tal que <code>interseccion xs ys<\/code> es la intersecci\u00f3n de las listas sin elementos repetidos <code>xs<\/code> e <code>ys<\/code>. Por ejemplo,<\/p>\n<pre lang=\"text\">\n   interseccion [3,2,5] [5,7,3,4]  ==  [3,5]\n   interseccion [3,2,5] [9,7,6,4]  ==  []\n<\/pre>\n<p><b>Soluciones en Haskell<\/b><\/p>\n<pre lang=\"haskell\">\nimport Data.List (nub, sort, intersect)\nimport qualified Data.Set as S (fromList, toList, intersection )\nimport Test.QuickCheck\n\n-- 1\u00aa soluci\u00f3n\n-- ===========\n\ninterseccion1 :: Eq a => [a] -> [a] -> [a]\ninterseccion1 xs ys =\n  [x | x <- xs, x `elem` ys]\n\n-- 2\u00aa soluci\u00f3n\n-- ===========\n\ninterseccion2 :: Ord a => [a] -> [a] -> [a]\ninterseccion2 [] _ = []\ninterseccion2 (x:xs) ys\n  | x `elem` ys = x : xs `interseccion2` ys\n  | otherwise   = xs `interseccion2` ys\n\n-- 3\u00aa soluci\u00f3n\n-- ===========\n\ninterseccion3 :: Ord a => [a] -> [a] -> [a]\ninterseccion3 = intersect\n\n-- 4\u00aa soluci\u00f3n\n-- ===========\n\ninterseccion4 :: Ord a => [a] -> [a] -> [a]\ninterseccion4 xs ys =\n  S.toList (S.fromList xs `S.intersection` S.fromList ys)\n\n-- Comprobaci\u00f3n de equivalencia\n-- ============================\n\n-- La propiedad es\nprop_interseccion :: [Int] -> [Int] -> Bool\nprop_interseccion xs ys =\n  all (== sort (xs' `interseccion1` ys'))\n      [sort (xs' `interseccion2` ys'),\n       sort (xs' `interseccion3` ys'),\n       xs' `interseccion4` ys']\n  where xs' = nub xs\n        ys' = nub ys\n\n-- La comprobaci\u00f3n es\n--    \u03bb> quickCheck prop_interseccion\n--    +++ OK, passed 100 tests.\n\n-- Comparaci\u00f3n de eficiencia\n-- =========================\n\n-- La comparaci\u00f3n es\n--    \u03bb> length (interseccion1 [0..3*10^4] [1,3..3*10^4])\n--    15000\n--    (2.94 secs, 6,673,360 bytes)\n--    \u03bb> length (interseccion2 [0..3*10^4] [1,3..3*10^4])\n--    15000\n--    (3.04 secs, 9,793,440 bytes)\n--    \u03bb> length (interseccion3 [0..3*10^4] [1,3..3*10^4])\n--    15000\n--    (5.39 secs, 6,673,472 bytes)\n--    \u03bb> length (interseccion4 [0..3*10^4] [1,3..3*10^4])\n--    15000\n--    (0.04 secs, 8,593,176 bytes)\n<\/pre>\n<p>El c\u00f3digo se encuentra en <a href=\"https:\/\/github.com\/jaalonso\/Exercitium\/blob\/main\/src\/Interseccion_conjuntista_de_listas.hs\">GitHub<\/a>.<\/p>\n<p><b>Soluciones en Python<\/b><\/p>\n<pre lang=\"python\">\nfrom typing import TypeVar\nfrom timeit import Timer, default_timer\nfrom sys import setrecursionlimit\nfrom hypothesis import given, strategies as st\n\nsetrecursionlimit(10**6)\n\nA = TypeVar('A')\n\n# 1\u00aa soluci\u00f3n\n# ===========\n\ndef interseccion1(xs: list[A], ys: list[A]) -> list[A]:\n    return [x for x in xs if x in ys]\n\n# 2\u00aa soluci\u00f3n\n# ===========\n\ndef interseccion2(xs: list[A], ys: list[A]) -> list[A]:\n    if not xs:\n        return []\n    if xs[0] in ys:\n        return [xs[0]] + interseccion2(xs[1:], ys)\n    return interseccion2(xs[1:], ys)\n\n# 3\u00aa soluci\u00f3n\n# ===========\n\ndef interseccion3(xs: list[A], ys: list[A]) -> list[A]:\n    zs = []\n    for x in xs:\n        if x in ys:\n            zs.append(x)\n    return zs\n\n# 4\u00aa soluci\u00f3n\n# ===========\n\ndef interseccion4(xs: list[A], ys: list[A]) -> list[A]:\n    return list(set(xs) & set(ys))\n\n# Comprobaci\u00f3n de equivalencia\n# ============================\n#\n# La propiedad es\n@given(st.lists(st.integers()),\n       st.lists(st.integers()))\ndef test_interseccion(xs, ys):\n    xs1 = list(set(xs))\n    ys1 = list(set(ys))\n    assert sorted(interseccion1(xs1, ys1)) ==\\\n           sorted(interseccion2(xs1, ys1)) ==\\\n           sorted(interseccion3(xs1, ys1)) ==\\\n           sorted(interseccion4(xs1, ys1))\n\n# La comprobaci\u00f3n es\n#    src> poetry run pytest -q interseccion_conjuntista_de_listas.py\n#    1 passed in 0.33s\n\n# Comparaci\u00f3n de eficiencia\n# =========================\n\ndef tiempo(e):\n    \"\"\"Tiempo (en segundos) de evaluar la expresi\u00f3n e.\"\"\"\n    t = Timer(e, \"\", default_timer, globals()).timeit(1)\n    print(f\"{t:0.2f} segundos\")\n\n# La comparaci\u00f3n es\n#    >>> tiempo('interseccion1(list(range(0,20000)), list(range(1,20000,2)))')\n#    0.98 segundos\n#    >>> tiempo('interseccion2(list(range(0,20000)), list(range(1,20000,2)))')\n#    2.13 segundos\n#    >>> tiempo('interseccion3(list(range(0,20000)), list(range(1,20000,2)))')\n#    0.87 segundos\n#    >>> tiempo('interseccion4(list(range(0,20000)), list(range(1,20000,2)))')\n#    0.00 segundos\n<\/pre>\n<p>El c\u00f3digo se encuentra en <a href=\"https:\/\/github.com\/jaalonso\/Exercitium-Python\/blob\/main\/src\/interseccion_conjuntista_de_listas.py\">GitHub<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Definir la funci\u00f3n interseccion :: Eq a => [a] -> [a] -> [a] tal que interseccion xs ys es la intersecci\u00f3n de las listas sin elementos repetidos xs e ys. Por ejemplo, interseccion [3,2,5] [5,7,3,4] == [3,5] interseccion [3,2,5] [9,7,6,4] == [] Soluciones en Haskell import Data.List (nub, sort, intersect) import qualified Data.Set as S&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"footnotes":"","_jetpack_memberships_contains_paid_content":false},"categories":[581],"tags":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7381"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/comments?post=7381"}],"version-history":[{"count":1,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7381\/revisions"}],"predecessor-version":[{"id":7382,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7381\/revisions\/7382"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/media?parent=7381"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/categories?post=7381"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/tags?post=7381"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}