{"id":7376,"date":"2022-09-20T06:00:37","date_gmt":"2022-09-20T04:00:37","guid":{"rendered":"http:\/\/www.glc.us.es\/~jalonso\/exercitium\/?p=7376"},"modified":"2022-12-14T14:28:02","modified_gmt":"2022-12-14T12:28:02","slug":"union-conjuntista-de-listas","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/union-conjuntista-de-listas\/","title":{"rendered":"Uni\u00f3n conjuntista de listas"},"content":{"rendered":"<p>Definir la funci\u00f3n<\/p>\n<pre lang=\"text\">\n   union :: Ord a => [a] -> [a] -> [a]\n<\/pre>\n<p>tal que <code>union xs ys<\/code> es la uni\u00f3n de las listas, sin elementos repetidos, <code>xs<\/code> e <code>ys<\/code>. Por ejemplo,<\/p>\n<pre lang=\"text\">\n   union [3,2,5] [5,7,3,4]  ==  [3,2,5,7,4]\n<\/pre>\n<p>Comprobar con QuickCheck que la uni\u00f3n es conmutativa.<\/p>\n<p><b>Soluciones<\/b><\/p>\n<p>A continuaci\u00f3n se muestran las <a href=\"#haskell\">soluciones en Haskell<\/a> y las <a href=\"#python\">soluciones en Python<\/a>.<\/p>\n<p><a name=\"haskell\"><\/a><br \/>\n<b>Soluciones en Haskell<\/b><\/p>\n<pre lang=\"haskell\">\nimport Data.List (nub, sort, union)\nimport qualified Data.Set as S (fromList, toList, union)\nimport Test.QuickCheck\n\n-- 1\u00aa soluci\u00f3n\n-- ===========\n\nunion1 :: Ord a => [a] -> [a] -> [a]\nunion1 xs ys = xs ++ [y | y <- ys, y `notElem` xs]\n\n-- 2\u00aa soluci\u00f3n\n-- ===========\n\nunion2 :: Ord a => [a] -> [a] -> [a]\nunion2 [] ys = ys\nunion2 (x:xs) ys\n  | x `elem` ys = xs `union2` ys\n  | otherwise   = x : xs `union2` ys\n\n-- 3\u00aa soluci\u00f3n\n-- ===========\n\nunion3 :: Ord a => [a] -> [a] -> [a]\nunion3 = union\n\n-- 4\u00aa soluci\u00f3n\n-- ===========\n\nunion4 :: Ord a => [a] -> [a] -> [a]\nunion4 xs ys =\n  S.toList (S.fromList xs `S.union` S.fromList ys)\n\n-- Comprobaci\u00f3n de equivalencia\n-- ============================\n\n-- La propiedad es\nprop_union :: [Int] -> [Int] -> Bool\nprop_union xs ys =\n  all (== sort (xs' `union1` ys'))\n      [sort (xs' `union2` ys'),\n       sort (xs' `union3` ys'),\n       xs' `union4` ys']\n  where xs' = nub xs\n        ys' = nub ys\n\n-- La comprobaci\u00f3n es\n--    \u03bb> quickCheck prop_union\n--    +++ OK, passed 100 tests.\n\n-- Comparaci\u00f3n de eficiencia\n-- =========================\n\n-- La comparaci\u00f3n es\n--    \u03bb> length (union1 [0,2..3*10^4] [1,3..3*10^4])\n--    30001\n--    (2.37 secs, 7,153,536 bytes)\n--    \u03bb> length (union2 [0,2..3*10^4] [1,3..3*10^4])\n--    30001\n--    (2.38 secs, 6,553,752 bytes)\n--    \u03bb> length (union3 [0,2..3*10^4] [1,3..3*10^4])\n--    30001\n--    (11.56 secs, 23,253,553,472 bytes)\n--    \u03bb> length (union4 [0,2..3*10^4] [1,3..3*10^4])\n--    30001\n--    (0.04 secs, 10,992,056 bytes)\n\n-- Comprobaci\u00f3n de la propiedad\n-- ============================\n\n-- La propiedad es\nprop_union_conmutativa :: [Int] -> [Int] -> Bool\nprop_union_conmutativa xs ys =\n  iguales (xs `union1` ys) (ys `union1` xs)\n\n-- (iguales xs ys) se verifica si xs e ys son iguales. Por ejemplo,\n--    iguales [3,2,3] [2,3]    ==  True\n--    iguales [3,2,3] [2,3,2]  ==  True\n--    iguales [3,2,3] [2,3,4]  ==  False\n--    iguales [2,3] [4,5]      ==  False\niguales :: Ord a => [a] -> [a] -> Bool\niguales xs ys =\n  S.fromList xs == S.fromList ys\n\n-- La comprobaci\u00f3n es\n--    \u03bb> quickCheck prop_union_conmutativa\n--    +++ OK, passed 100 tests.\n<\/pre>\n<p>El c\u00f3digo se encuentra en <a href=\"https:\/\/github.com\/jaalonso\/Exercitium\/blob\/main\/src\/Union_conjuntista_de_listas.hs\">GitHub<\/a>.<\/p>\n<p><a name=\"python\"><\/a><br \/>\n<b>Soluciones en Python<\/b><\/p>\n<pre lang=\"python\">\nfrom typing import TypeVar\nfrom timeit import Timer, default_timer\nfrom sys import setrecursionlimit\nfrom hypothesis import given, strategies as st\n\nsetrecursionlimit(10**6)\n\nA = TypeVar('A')\n\n# 1\u00aa soluci\u00f3n\n# ===========\n\ndef union1(xs: list[A], ys: list[A]) -> list[A]:\n    return xs + [y for y in ys if y not in xs]\n\n# 2\u00aa soluci\u00f3n\n# ===========\n\ndef union2(xs: list[A], ys: list[A]) -> list[A]:\n    if not xs:\n        return ys\n    if xs[0] in ys:\n        return union2(xs[1:], ys)\n    return [xs[0]] + union2(xs[1:], ys)\n\n# 3\u00aa soluci\u00f3n\n# ===========\n\ndef union3(xs: list[A], ys: list[A]) -> list[A]:\n    zs = ys[:]\n    for x in xs:\n        if x not in ys:\n            zs.append(x)\n    return zs\n\n# 4\u00aa soluci\u00f3n\n# ===========\n\ndef union4(xs: list[A], ys: list[A]) -> list[A]:\n    return list(set(xs) | set(ys))\n\n# Comprobaci\u00f3n de equivalencia\n# ============================\n#\n# La propiedad es\n@given(st.lists(st.integers()),\n       st.lists(st.integers()))\ndef test_union(xs, ys):\n    xs1 = list(set(xs))\n    ys1 = list(set(ys))\n    assert sorted(union1(xs1, ys1)) ==\\\n           sorted(union2(xs1, ys1)) ==\\\n           sorted(union3(xs1, ys1)) ==\\\n           sorted(union4(xs1, ys1))\n\n# La comprobaci\u00f3n es\n#    src> poetry run pytest -q union_conjuntista_de_listas.py\n#    1 passed in 0.36s\n\n# Comparaci\u00f3n de eficiencia\n# =========================\n\ndef tiempo(e):\n    \"\"\"Tiempo (en segundos) de evaluar la expresi\u00f3n e.\"\"\"\n    t = Timer(e, \"\", default_timer, globals()).timeit(1)\n    print(f\"{t:0.2f} segundos\")\n\n# La comparaci\u00f3n es\n#    >>> tiempo('union1(list(range(0,30000,2)), list(range(1,30000,2)))')\n#    1.30 segundos\n#    >>> tiempo('union2(list(range(0,30000,2)), list(range(1,30000,2)))')\n#    2.84 segundos\n#    >>> tiempo('union3(list(range(0,30000,2)), list(range(1,30000,2)))')\n#    1.45 segundos\n#    >>> tiempo('union4(list(range(0,30000,2)), list(range(1,30000,2)))')\n#    0.00 segundos\n\n# Comprobaci\u00f3n de la propiedad\n# ============================\n\n# iguales(xs, ys) se verifica si xs e ys son iguales como conjuntos. Por\n# ejemplo,\n#    iguales([3,2,3], [2,3])    ==  True\n#    iguales([3,2,3], [2,3,2])  ==  True\n#    iguales([3,2,3], [2,3,4])  ==  False\n#    iguales([2,3], [4,5])      ==  False\ndef iguales(xs: list[A], ys: list[A]) -> bool:\n    return set(xs) == set(ys)\n\n# La propiedad es\n@given(st.lists(st.integers()),\n       st.lists(st.integers()))\ndef test_union_conmutativa(xs, ys):\n    xs1 = list(set(xs))\n    ys1 = list(set(ys))\n    assert iguales(union1(xs1, ys1), union1(ys1, xs1))\n\n# La comprobaci\u00f3n es\n#    src> poetry run pytest -q union_conjuntista_de_listas.py\n#    2 passed in 0.49s\n<\/pre>\n<p>El c\u00f3digo se encuentra en <a href=\"https:\/\/github.com\/jaalonso\/Exercitium-Python\/blob\/main\/src\/union_conjuntista_de_listas.py\">GitHub<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Definir la funci\u00f3n union :: Ord a => [a] -> [a] -> [a] tal que union xs ys es la uni\u00f3n de las listas, sin elementos repetidos, xs e ys. Por ejemplo, union [3,2,5] [5,7,3,4] == [3,2,5,7,4] Comprobar con QuickCheck que la uni\u00f3n es conmutativa. Soluciones A continuaci\u00f3n se muestran las soluciones en Haskell y&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"footnotes":"","_jetpack_memberships_contains_paid_content":false},"categories":[581],"tags":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7376"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/comments?post=7376"}],"version-history":[{"count":3,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7376\/revisions"}],"predecessor-version":[{"id":7688,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7376\/revisions\/7688"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/media?parent=7376"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/categories?post=7376"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/tags?post=7376"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}