{"id":7359,"date":"2022-09-13T06:00:32","date_gmt":"2022-09-13T04:00:32","guid":{"rendered":"http:\/\/www.glc.us.es\/~jalonso\/exercitium\/?p=7359"},"modified":"2022-12-14T14:32:34","modified_gmt":"2022-12-14T12:32:34","slug":"formula-de-heron-para-el-area-de-un-triangulo","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/formula-de-heron-para-el-area-de-un-triangulo\/","title":{"rendered":"F\u00f3rmula de Her\u00f3n para el \u00e1rea de un tri\u00e1ngulo"},"content":{"rendered":"<p>La f\u00f3rmula de Her\u00f3n, descubierta por Her\u00f3n de Alejandr\u00eda, dice que el \u00e1rea de un tri\u00e1ngulo cuyo lados miden a, b y c es la ra\u00edz cuadrada de s(s-a)(s-b)(s-c) donde s es el semiper\u00edmetro<\/p>\n<pre lang=\"text\">\n   s = (a+b+c)\/2\n<\/pre>\n<p>Definir la funci\u00f3n<\/p>\n<pre lang=\"text\">\n   area :: Double -> Double -> Double -> Double\n<\/pre>\n<p>tal que <code>(area a b c)<\/code> es el \u00e1rea del tri\u00e1ngulo de lados <code>a<\/code>, <code>b<\/code> y <code>c<\/code>. Por ejemplo,<\/p>\n<pre lang=\"text\">\n   area 3 4 5  ==  6.0\n<\/pre>\n<p><b>Soluciones<\/b><\/p>\n<p>A continuaci\u00f3n se muestran las <a href=\"#haskell\">soluciones en Haskell<\/a> y las <a href=\"#python\">soluciones en Python<\/a>.<\/p>\n<p><a name=\"haskell\"><\/a><br \/>\n<b>Soluciones en Haskell<\/b><\/p>\n<pre lang=\"haskell\">\narea :: Double -> Double -> Double -> Double\narea a b c = sqrt (s*(s-a)*(s-b)*(s-c))\n  where s = (a+b+c)\/2\n<\/pre>\n<p>El c\u00f3digo se encuentra en <a href=\"https:\/\/github.com\/jaalonso\/Exercitium\/blob\/main\/src\/Formula_de_Heron_para_el_area_de_un_triangulo.hs\">GitHub<\/a>.<\/p>\n<p><a name=\"python\"><\/a><br \/>\n<b>Soluciones en Python<\/b><\/p>\n<pre lang=\"python\">\nfrom math import sqrt\n\ndef area(a: float, b: float, c: float) -> float:\n    s = (a+b+c)\/2\n    return sqrt(s*(s-a)*(s-b)*(s-c))\n<\/pre>\n<p>El c\u00f3digo se encuentra en <a href=\"https:\/\/github.com\/jaalonso\/Exercitium-Python\/blob\/main\/src\/formula_de_Heron_para_el_area_de_un_triangulo.py\">GitHub<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>La f\u00f3rmula de Her\u00f3n, descubierta por Her\u00f3n de Alejandr\u00eda, dice que el \u00e1rea de un tri\u00e1ngulo cuyo lados miden a, b y c es la ra\u00edz cuadrada de s(s-a)(s-b)(s-c) donde s es el semiper\u00edmetro s = (a+b+c)\/2 Definir la funci\u00f3n area :: Double -> Double -> Double -> Double tal que (area a b c)&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"footnotes":"","_jetpack_memberships_contains_paid_content":false},"categories":[581],"tags":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7359"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/comments?post=7359"}],"version-history":[{"count":3,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7359\/revisions"}],"predecessor-version":[{"id":7693,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/7359\/revisions\/7693"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/media?parent=7359"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/categories?post=7359"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/tags?post=7359"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}