{"id":4343,"date":"2018-11-28T06:00:55","date_gmt":"2018-11-28T04:00:55","guid":{"rendered":"http:\/\/www.glc.us.es\/~jalonso\/exercitium\/?p=4343"},"modified":"2019-01-19T12:12:07","modified_gmt":"2019-01-19T10:12:07","slug":"elemento-solitario","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/elemento-solitario\/","title":{"rendered":"Elemento solitario"},"content":{"rendered":"<p>Definir la funci\u00f3n<\/p>\n<pre lang=\"text\">\n   solitario :: Ord a => [a] -> a\n<\/pre>\n<p>tal que (solitario xs) es el \u00fanico elemento que ocurre una vez en la lista xs (se supone que la lista xs tiene al menos 3 elementos y todos son iguales menos uno que es el solitario). Por ejemplo,<\/p>\n<pre lang=\"text\">\n   solitario [2,2,7,2]  ==  7\n   solitario [2,2,2,7]  ==  7\n   solitario [7,2,2,2]  ==  7\n   solitario (replicate (2*10^7) 1 ++ [2])  ==  2\n<\/pre>\n<h4>Soluciones<\/h4>\n<pre lang=\"haskell\">\nimport Test.QuickCheck \nimport Data.List (group, nub, sort)\n\n-- 1\u00aa definici\u00f3n\n-- =============\n\nsolitario :: Ord a => [a] -> a\nsolitario xs =\n  head [x | x <- xs\n          , cuenta xs x == 1]\n\ncuenta :: Eq a => [a] -> a -> Int\ncuenta xs x = length [y | y <- xs\n                        , x == y]\n\n-- 2\u00aa definici\u00f3n\n-- =============\n\nsolitario2 :: Ord a => [a] -> a\nsolitario2 xs = head (filter (\\x -> cuenta2 xs x == 1) xs)\n\ncuenta2 :: Eq a => [a] -> a -> Int\ncuenta2 xs x = length (filter (==x) xs)\n\n-- 3\u00aa definici\u00f3n\n-- =============\n\nsolitario3 :: Ord a => [a] -> a\nsolitario3 [x] = x\nsolitario3 (x1:x2:x3:xs)\n  | x1 \/= x2 && x2 == x3 = x1\n  | x1 == x2 && x2 \/= x3 = x3\n  | otherwise            = solitario3 (x2:x3:xs)\n\n-- 4\u00aa definici\u00f3n\n-- =============\n\nsolitario4 :: Ord a => [a] -> a\nsolitario4 xs \n  | y1 == y2  = last ys\n  | otherwise = y1\n  where (y1:y2:ys) = sort xs\n\n-- 5\u00aa definici\u00f3n\n-- =============\n\nsolitario5 :: Ord a => [a] -> a\nsolitario5 xs | null ys   = y\n              | otherwise = z\n  where [y:ys,z:zs] = group (sort xs)\n\n-- 6\u00aa definici\u00f3n\n-- =============\n\nsolitario6 :: Ord a => [a] -> a\nsolitario6 xs =\n  head [x | x <- nub xs\n          , cuenta xs x == 1]\n\n-- 7\u00aa definici\u00f3n\n-- =============\n\nsolitario7 :: Ord a => [a] -> a\nsolitario7 (a:b:xs)\n  | a == b        = solitario7 (b:xs)\n  | elem a (b:xs) = b\n  | elem b (a:xs) = a\nsolitario7 [a,b] = b\n\n-- Equivalencia\n-- ============\n\n-- Propiedad de equivalencia\nprop_solitario_equiv :: Property\nprop_solitario_equiv =\n  forAll listaSolitaria (\\xs -> solitario xs == solitario2 xs &&\n                                solitario xs == solitario3 xs &&\n                                solitario xs == solitario4 xs &&\n                                solitario xs == solitario5 xs &&\n                                solitario xs == solitario6 xs &&\n                                solitario xs == solitario7 xs)\n\n-- Generador de listas con al menos 3 elementos y todos iguales menos\n-- uno. Por ejemplo,\n--    \u03bb> sample listaSolitaria\n--    [1,0,0,0,0]\n--    [0,0,-1,0,0,0]\n--    [4,1,1,1]\n--    [6,6,4,6]\n--    [8,8,8,8,8,-4,8,8,8,8,8,8]\n--    ...\nlistaSolitaria :: Gen [Int]\nlistaSolitaria = do\n  n <- arbitrary\n  m <- arbitrary `suchThat` (\\a -> n + a > 2)\n  x <- arbitrary\n  y <- arbitrary `suchThat` (\\a -> a \/= x)\n  return (replicate n x ++ [y] ++ replicate m x)\n\n-- Comprobaci\u00f3n:\n--    \u03bb> quickCheck prop_solitario_equiv\n--    +++ OK, passed 100 tests.\n\n-- Comparaci\u00f3n de eficiencia:\n--    \u03bb> solitario (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (5.47 secs, 3,202,688,152 bytes)\n--    \u03bb> solitario2 (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (2.08 secs, 1,401,603,960 bytes)\n--    \u03bb> solitario3 (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (0.04 secs, 3,842,240 bytes)\n--    \u03bb> solitario4 (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (0.02 secs, 1,566,472 bytes)\n--    \u03bb> solitario5 (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (0.01 secs, 927,064 bytes)\n--    \u03bb> solitario6 (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (0.01 secs, 1,604,176 bytes)\n--    \u03bb> solitario7 (replicate (5*10^3) 1 ++ [2])\n--    2\n--    (0.01 secs, 1,923,440 bytes)\n--    \n--    \u03bb> solitario3 (replicate (5*10^6) 1 ++ [2])\n--    2\n--    (4.62 secs, 3,720,123,560 bytes)\n--    \u03bb> solitario4 (replicate (5*10^6) 1 ++ [2])\n--    2\n--    (1.48 secs, 1,440,124,240 bytes)\n--    \u03bb> solitario5 (replicate (5*10^6) 1 ++ [2])\n--    2\n--    (1.40 secs, 1,440,125,936 bytes)\n--    \u03bb> solitario6 (replicate (5*10^6) 1 ++ [2])\n--    2\n--    (2.65 secs, 1,480,125,032 bytes)\n--    \u03bb> solitario7 (replicate (5*10^6) 1 ++ [2])\n--    2\n--    (2.21 secs, 1,800,126,224 bytes)\n--    \n--    \u03bb> solitario5 (2 : replicate (5*10^6) 1)\n--    2\n--    (1.38 secs, 1,520,127,864 bytes)\n--    \u03bb> solitario6 (2 : replicate (5*10^6) 1)\n--    2\n--    (1.18 secs, 560,127,664 bytes)\n--    \u03bb> solitario7 (2 : replicate (5*10^6) 1)\n--    2\n--    (0.29 secs, 280,126,888 bytes)\n<\/pre>\n<h4>Pensamiento<\/h4>\n<blockquote><p>\nSube y sube, pero ten<br \/>\ncuidado Nefelibata,<br \/>\nque entre las nubes tambi\u00e9n,<br \/>\nse puede meter la pata.<\/p>\n<p>Antonio Machado\n<\/p><\/blockquote>\n","protected":false},"excerpt":{"rendered":"<p>Definir la funci\u00f3n solitario :: Ord a => [a] -> a tal que (solitario xs) es el \u00fanico elemento que ocurre una vez en la lista xs (se supone que la lista xs tiene al menos 3 elementos y todos son iguales menos uno que es el solitario). Por ejemplo, solitario [2,2,7,2] == 7 solitario&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"footnotes":"","_jetpack_memberships_contains_paid_content":false},"categories":[5],"tags":[8,38,13,71,134,28,141,11,6,14],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/4343"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/comments?post=4343"}],"version-history":[{"count":5,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/4343\/revisions"}],"predecessor-version":[{"id":4591,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/posts\/4343\/revisions\/4591"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/media?parent=4343"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/categories?post=4343"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/exercitium\/wp-json\/wp\/v2\/tags?post=4343"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}