        {"id":499,"date":"2021-06-25T06:00:24","date_gmt":"2021-06-25T04:00:24","guid":{"rendered":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/?p=499"},"modified":"2021-06-16T17:01:53","modified_gmt":"2021-06-16T15:01:53","slug":"imagen-de-la-interseccion-general-mediante-inyectiva","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/imagen-de-la-interseccion-general-mediante-inyectiva\/","title":{"rendered":"Imagen de la intersecci\u00f3n general mediante inyectiva"},"content":{"rendered":"<p>Demostrar que si f es inyectiva, entonces<\/p>\n<pre lang=\"text\">\n   (\u22c2 i, f[A i]) \u2286 f[\u22c2 i, A i]\n<\/pre>\n<p>Para ello, completar la siguiente teor\u00eda de Lean:<\/p>\n<pre lang=\"lean\">\nimport data.set.basic\nimport tactic\n\nopen set function\n\nvariables {\u03b1 : Type*} {\u03b2 : Type*} {I : Type*}\nvariable  f : \u03b1 \u2192 \u03b2\nvariables A : I \u2192 set \u03b1\n\nexample\n  (i : I)\n  (injf : injective f)\n  : (\u22c2 i, f '' A i) \u2286 f '' (\u22c2 i, A i) :=\nsorry\n<\/pre>\n<p>[expand title=\u00bbSoluciones con Lean\u00bb]<\/p>\n<pre lang=\"lean\">\r\nimport data.set.basic\r\nimport tactic\r\n\r\nopen set function\r\n\r\nvariables {\u03b1 : Type*} {\u03b2 : Type*} {I : Type*}\r\nvariable  f : \u03b1 \u2192 \u03b2\r\nvariables A : I \u2192 set \u03b1\r\n\r\n-- 1\u00aa demostraci\u00f3n\r\n-- ===============\r\n\r\nexample\r\n  (i : I)\r\n  (injf : injective f)\r\n  : (\u22c2 i, f '' A i) \u2286 f '' (\u22c2 i, A i) :=\r\nbegin\r\n  intros y hy,\r\n  rw mem_Inter at hy,\r\n  rcases hy i with \u27e8x, xAi, fxy\u27e9,\r\n  use x,\r\n  split,\r\n  { apply mem_Inter_of_mem,\r\n    intro j,\r\n    rcases hy j with \u27e8z, zAj, fzy\u27e9,\r\n    convert zAj,\r\n    apply injf,\r\n    rw fxy,\r\n    rw \u2190 fzy, },\r\n  { exact fxy, },\r\nend\r\n\r\n-- 2\u00aa demostraci\u00f3n\r\n-- ===============\r\n\r\nexample\r\n  (i : I)\r\n  (injf : injective f)\r\n  : (\u22c2 i, f '' A i) \u2286 f '' (\u22c2 i, A i) :=\r\nbegin\r\n  intro y,\r\n  simp,\r\n  intro h,\r\n  rcases h i with \u27e8x, xAi, fxy\u27e9,\r\n  use x,\r\n  split,\r\n  { intro j,\r\n    rcases h j with \u27e8z, zAi, fzy\u27e9,\r\n    have : f x = f z, by rw [fxy, fzy],\r\n    have : x = z, from injf this,\r\n    rw this,\r\n    exact zAi, },\r\n  { exact fxy, },\r\nend\r\n<\/pre>\n<p>Se puede interactuar con la prueba anterior en <a href=\"https:\/\/www.cs.us.es\/~jalonso\/lean-web-editor\/#url=https:\/\/raw.githubusercontent.com\/jaalonso\/Calculemus\/main\/src\/Imagen_de_la_interseccion_general_mediante_inyectiva.lean\" rel=\"noopener noreferrer\" target=\"_blank\">esta sesi\u00f3n con Lean<\/a>,<\/p>\n<p>En los comentarios se pueden escribir otras soluciones, escribiendo el c\u00f3digo entre una l\u00ednea con &#60;pre lang=&quot;isar&quot;&#62; y otra con &#60;\/pre&#62;<br \/>\n[\/expand]<\/p>\n<p>[expand title=\u00bbSoluciones con Isabelle\/HOL\u00bb]<\/p>\n<pre lang=\"isar\">\r\n<\/pre>\n<p>En los comentarios se pueden escribir otras soluciones, escribiendo el c\u00f3digo entre una l\u00ednea con &#60;pre lang=&quot;isar&quot;&#62; y otra con &#60;\/pre&#62;<br \/>\n[\/expand]<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Demostrar que si f es inyectiva, entonces (\u22c2 i, f[A i]) \u2286 f[\u22c2 i, A i] Para ello, completar la siguiente teor\u00eda de Lean: import data.set.basic import tactic open set function variables {\u03b1 : Type*} {\u03b2 : Type*} {I : Type*} variable f : \u03b1 \u2192 \u03b2 variables A : I \u2192 set \u03b1 example (i : I) (injf : injective f) : (\u22c2 i, f \u00bb A i) \u2286 f \u00bb (\u22c2 i, A i) := sorry [expand title=\u00bbSoluciones con Lean\u00bb] import data.set.basic import tactic open set function variables {\u03b1 : Type*} {\u03b2 : Type*} {I : Type*} variable f : \u03b1 \u2192 \u03b2 variables A : I \u2192 set \u03b1 &#8212; 1\u00aa demostraci\u00f3n &#8212; =============== example (i : I) (injf : injective f)&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[7],"tags":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/499"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/comments?post=499"}],"version-history":[{"count":1,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/499\/revisions"}],"predecessor-version":[{"id":500,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/499\/revisions\/500"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/media?parent=499"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/categories?post=499"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/tags?post=499"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}