        {"id":2393,"date":"2024-04-16T13:37:50","date_gmt":"2024-04-16T11:37:50","guid":{"rendered":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/?p=2393"},"modified":"2024-04-16T13:37:50","modified_gmt":"2024-04-16T11:37:50","slug":"16-abr-24","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/16-abr-24\/","title":{"rendered":"f[s] \\ f[t] \u2286 f[s \\ t]"},"content":{"rendered":"\n<p>Demostrar con Lean4 que<br \/>\n&#92;[f[s] &#92;setminus f[t] \u2286 f[s &#92;setminus t] &#92;]<\/p>\n<p>Para ello, completar la siguiente teor\u00eda de Lean4:<\/p>\n<pre lang=\"lean\">\nimport Mathlib.Data.Set.Function\nimport Mathlib.Tactic\n\nopen Set\n\nvariable {\u03b1 \u03b2 : Type _}\nvariable (f : \u03b1 \u2192 \u03b2)\nvariable (s t : Set \u03b1)\n\nexample : f '' s \\ f '' t \u2286 f '' (s \\ t) :=\nby sorry\n<\/pre>\n<p><!--more--><\/p>\n<h2>1. Demostraci\u00f3n en lenguaje natural<\/h2>\n<p>Sea &#92;(y \u2208 f[s] &#92;setminus f[t]&#92;). Entonces,<br \/>\n&#92;begin{align}<br \/>\n   &amp;y \u2208 f[s] &#92;tag{1} &#92;&#92;<br \/>\n   &amp;y \u2209 f[t] &#92;tag{2}<br \/>\n&#92;end{align}<br \/>\nPor (1), existe un &#92;(x&#92;) tal que<br \/>\n&#92;begin{align}<br \/>\n   &amp;x \u2208 s    &#92;tag{3} &#92;&#92;<br \/>\n   &amp;f(x) = y &#92;tag{4}<br \/>\n&#92;end{align}<br \/>\nPor tanto, para demostrar que &#92;(y \u2208 f[s &#92;setminus t]&#92;), basta probar que &#92;(x \u2209 t&#92;). Para ello, supongamos que &#92;(x \u2208 t&#92;). Entonces, por (4), &#92;(y \u2208 f[t]&#92;), en contradicci\u00f3n con (2).<\/p>\n<h2>2. Demostraciones con Lean4<\/h2>\n<pre lang=\"lean\">\nimport Mathlib.Data.Set.Function\nimport Mathlib.Tactic\n\nopen Set\n\nvariable {\u03b1 \u03b2 : Type _}\nvariable (f : \u03b1 \u2192 \u03b2)\nvariable (s t : Set \u03b1)\n\n-- 1\u00aa demostraci\u00f3n\n-- ===============\n\nexample : f '' s \\ f '' t \u2286 f '' (s \\ t) :=\nby\n  intros y hy\n  -- y : \u03b2\n  -- hy : y \u2208 f '' s \\ f '' t\n  -- \u22a2 y \u2208 f '' (s \\ t)\n  rcases hy with \u27e8yfs, ynft\u27e9\n  -- yfs : y \u2208 f '' s\n  -- ynft : \u00acy \u2208 f '' t\n  rcases yfs with \u27e8x, hx\u27e9\n  -- x : \u03b1\n  -- hx : x \u2208 s \u2227 f x = y\n  rcases hx with \u27e8xs, fxy\u27e9\n  -- xs : x \u2208 s\n  -- fxy : f x = y\n  have h1 : x \u2209 t := by\n    intro xt\n    -- xt : x \u2208 t\n    -- \u22a2 False\n    have h2 : f x \u2208 f '' t := mem_image_of_mem f xt\n    have h3 : y \u2208 f '' t := by rwa [fxy] at h2\n    show False\n    exact ynft h3\n  have h4 : x \u2208 s \\ t := mem_diff_of_mem xs h1\n  have h5 : f x \u2208 f '' (s \\ t) := mem_image_of_mem f h4\n  show y \u2208 f '' (s \\ t)\n  rwa [fxy] at h5\n\n-- 2\u00aa demostraci\u00f3n\n-- ===============\n\nexample : f '' s \\ f '' t \u2286 f '' (s \\ t) :=\nby\n  intros y hy\n  -- y : \u03b2\n  -- hy : y \u2208 f '' s \\ f '' t\n  -- \u22a2 y \u2208 f '' (s \\ t)\n  rcases hy with \u27e8yfs, ynft\u27e9\n  -- yfs : y \u2208 f '' s\n  -- ynft : \u00acy \u2208 f '' t\n  rcases yfs with \u27e8x, hx\u27e9\n  -- x : \u03b1\n  -- hx : x \u2208 s \u2227 f x = y\n  rcases hx with \u27e8xs, fxy\u27e9\n  -- xs : x \u2208 s\n  -- fxy : f x = y\n  use x\n  -- \u22a2 x \u2208 s \\ t \u2227 f x = y\n  constructor\n  . -- \u22a2 x \u2208 s \\ t\n    constructor\n    . -- \u22a2 x \u2208 s\n      exact xs\n    . -- \u22a2 \u00acx \u2208 t\n      intro xt\n      -- xt : x \u2208 t\n      -- \u22a2 False\n      apply ynft\n      -- \u22a2 y \u2208 f '' t\n      rw [\u2190fxy]\n      -- \u22a2 f x \u2208 f '' t\n      apply mem_image_of_mem\n      -- \u22a2 x \u2208 t\n      exact xt\n  . -- \u22a2 f x = y\n    exact fxy\n\n-- 3\u00aa demostraci\u00f3n\n-- ===============\n\nexample : f '' s \\ f '' t \u2286 f '' (s \\ t) :=\nby\n  rintro y \u27e8\u27e8x, xs, fxy\u27e9, ynft\u27e9\n  -- y : \u03b2\n  -- ynft : \u00acy \u2208 f '' t\n  -- x : \u03b1\n  -- xs : x \u2208 s\n  -- fxy : f x = y\n  -- \u22a2 y \u2208 f '' (s \\ t)\n  use x\n  -- \u22a2 x \u2208 s \\ t \u2227 f x = y\n  aesop\n\n-- 4\u00aa demostraci\u00f3n\n-- ===============\n\nexample : f '' s \\ f '' t \u2286 f '' (s \\ t) :=\nfun y \u27e8\u27e8x, xs, fxy\u27e9, ynft\u27e9 \u21a6 \u27e8x, by aesop\u27e9\n\n-- 5\u00aa demostraci\u00f3n\n-- ===============\n\nexample : f '' s \\ f '' t \u2286 f '' (s \\ t) :=\nsubset_image_diff f s t\n\n-- Lemmas usados\n-- =============\n\n-- variable (x : \u03b1)\n-- #check (mem_image_of_mem f : x  \u2208 s \u2192 f x \u2208 f '' s)\n-- #check (subset_image_diff f s t : f '' s \\ f '' t \u2286 f '' (s \\ t))\n<\/pre>\n<p>Se puede interactuar con las demostraciones anteriores en <a href=\"https:\/\/live.lean-lang.org\/#url=https:\/\/raw.githubusercontent.com\/jaalonso\/Calculemus2\/main\/src\/Imagen_de_la_diferencia_de_conjuntos.lean\" rel=\"noopener noreferrer\" target=\"_blank\">Lean 4 Web<\/a>.<\/p>\n<h2>3. Demostraciones con Isabelle\/HOL<\/h2>\n<pre lang=\"isar\">\ntheory Imagen_de_la_diferencia_de_conjuntos\nimports Main\nbegin\n\n(* 1\u00aa demostraci\u00f3n *)\n\nlemma \"f ` s - f ` t \u2286 f ` (s - t)\"\nproof (rule subsetI)\n  fix y\n  assume hy : \"y \u2208 f ` s - f ` t\"\n  then show \"y \u2208 f ` (s - t)\"\n  proof (rule DiffE)\n    assume \"y \u2208 f ` s\"\n    assume \"y \u2209 f ` t\"\n    note \u2039y \u2208 f ` s\u203a\n    then show \"y \u2208 f ` (s - t)\"\n    proof (rule imageE)\n      fix x\n      assume \"y = f x\"\n      assume \"x \u2208 s\"\n      have \u2039x \u2209 t\u203a\n      proof (rule notI)\n        assume \"x \u2208 t\"\n        then have \"f x \u2208 f ` t\"\n          by (rule imageI)\n        with \u2039y = f x\u203a have \"y \u2208 f ` t\"\n          by (rule ssubst)\n      with \u2039y \u2209 f ` t\u203a show False\n        by (rule notE)\n    qed\n    with \u2039x \u2208 s\u203a have \"x \u2208 s - t\"\n      by (rule DiffI)\n    then have \"f x \u2208 f ` (s - t)\"\n      by (rule imageI)\n    with \u2039y = f x\u203a show \"y \u2208 f ` (s - t)\"\n      by (rule ssubst)\n    qed\n  qed\nqed\n\n(* 2\u00aa demostraci\u00f3n *)\n\nlemma \"f ` s - f ` t \u2286 f ` (s - t)\"\nproof\n  fix y\n  assume hy : \"y \u2208 f ` s - f ` t\"\n  then show \"y \u2208 f ` (s - t)\"\n  proof\n    assume \"y \u2208 f ` s\"\n    assume \"y \u2209 f ` t\"\n    note \u2039y \u2208 f ` s\u203a\n    then show \"y \u2208 f ` (s - t)\"\n    proof\n      fix x\n      assume \"y = f x\"\n      assume \"x \u2208 s\"\n      have \u2039x \u2209 t\u203a\n      proof\n        assume \"x \u2208 t\"\n        then have \"f x \u2208 f ` t\" by simp\n        with \u2039y = f x\u203a have \"y \u2208 f ` t\" by simp\n      with \u2039y \u2209 f ` t\u203a show False by simp\n    qed\n    with \u2039x \u2208 s\u203a have \"x \u2208 s - t\" by simp\n    then have \"f x \u2208 f ` (s - t)\" by simp\n    with \u2039y = f x\u203a show \"y \u2208 f ` (s - t)\" by simp\n    qed\n  qed\nqed\n\n(* 3\u00aa demostraci\u00f3n *)\n\nlemma \"f ` s - f ` t \u2286 f ` (s - t)\"\n  by (simp only: image_diff_subset)\n\n(* 4\u00aa demostraci\u00f3n *)\n\nlemma \"f ` s - f ` t \u2286 f ` (s - t)\"\n  by auto\n\nend\n<\/pre>\n","protected":false},"excerpt":{"rendered":"<p>Demostrar con Lean4 que &#92;[f[s] &#92;setminus f[t] \u2286 f[s &#92;setminus t] &#92;] Para ello, completar la siguiente teor\u00eda de Lean4: import Mathlib.Data.Set.Function import Mathlib.Tactic open Set variable {\u03b1 \u03b2 : Type _} variable (f : \u03b1 \u2192 \u03b2) variable (s t : Set \u03b1) example : f \u00bb s \\ f \u00bb t \u2286 f \u00bb (s \\ t) := by sorry<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"default","_kad_post_title":"default","_kad_post_layout":"default","_kad_post_sidebar_id":"","_kad_post_content_style":"default","_kad_post_vertical_padding":"default","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[17],"tags":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/2393"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/comments?post=2393"}],"version-history":[{"count":1,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/2393\/revisions"}],"predecessor-version":[{"id":2394,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/2393\/revisions\/2394"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/media?parent=2393"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/categories?post=2393"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/tags?post=2393"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}