        {"id":1438,"date":"2023-08-08T06:00:00","date_gmt":"2023-08-08T04:00:00","guid":{"rendered":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/?p=1438"},"modified":"2023-07-28T18:45:22","modified_gmt":"2023-07-28T16:45:22","slug":"08-ago-23","status":"publish","type":"post","link":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/08-ago-23\/","title":{"rendered":"Si R es un anillo y a, b \u2208 R tales que a+b=0, entonces a=-b"},"content":{"rendered":"<p>Demostrar con Lean4 que si R es un anillo y a, b \u2208 R tales que<\/p>\n<pre lang=\"text\">\r\n   a + b = 0\r\n<\/pre>\n<p>entonces<\/p>\n<pre lang=\"text\">\r\n   a = -b\r\n<\/pre>\n<p>Para ello, completar la siguiente teor\u00eda de Lean4:<\/p>\n<pre lang=\"lean\">\r\nimport Mathlib.Algebra.Ring.Defs\r\nimport Mathlib.Tactic\r\n\r\nvariable {R : Type _} [Ring R]\r\nvariable {a b : R}\r\n\r\nexample\r\n  (h : a + b = 0)\r\n  : a = -b :=\r\nsorry\r\n<\/pre>\n<p><!--more--><\/p>\n<p><b>Demostraci\u00f3n en lenguaje natural<\/b><\/p>\n<p><br \/>\n<b>1\u00aa demostraci\u00f3n en LN<\/b><\/p>\n<p>Por la siguiente cadena de igualdades<br \/>\n\\begin{align}<br \/>\n   a &#038;= (a + b) + -b    &#038;&#038;\\text{[por la concelativa]} \\\\<br \/>\n     &#038;= 0 + -b          &#038;&#038;\\text{[por la hip\u00f3tesis]} \\\\<br \/>\n     &#038;= -b              &#038;&#038;\\text{[por la suma con cero]}<br \/>\n\\end{align}<\/p>\n<p><b>2\u00aa demostraci\u00f3n en LN<\/b><\/p>\n<p>Sumando \\(-a\\) a ambos lados de la hip\u00f3tesis, se tiene<br \/>\n\\[(a + b) + -b = 0 + -b\\]<br \/>\nEl t\u00e9rmino de la izquierda se reduce a \\(a\\) (por la cancelativa) y el de la derecha a \\(-b\\) (por la suma con cero). Por tanto, se tiene<br \/>\n\\[a = -b\\]<\/p>\n<p><b>Demostraciones con Lean4<\/b><\/p>\n<pre lang=\"lean\">\r\nimport Mathlib.Algebra.Ring.Defs\r\nimport Mathlib.Tactic\r\n\r\nvariable {R : Type _} [Ring R]\r\nvariable {a b : R}\r\n\r\n-- 1\u00aa demostraci\u00f3n (basada en la 1\u00aa en LN)\r\nexample\r\n  (h : a + b = 0)\r\n  : a = -b :=\r\ncalc\r\n  a = (a + b) + -b := by rw [add_neg_cancel_right]\r\n  _ = 0 + -b       := by rw [h]\r\n  _ = -b           := by rw [zero_add]\r\n\r\n-- 2\u00aa demostraci\u00f3n (basada en la 1\u00aa en LN)\r\nexample\r\n  (h : a + b = 0)\r\n  : a = -b :=\r\ncalc\r\n  a = (a + b) + -b := by simp\r\n  _ = 0 + -b       := by rw [h]\r\n  _ = -b           := by simp\r\n\r\n-- 3\u00aa demostraci\u00f3n (basada en la 1\u00aa en LN)\r\nexample\r\n  (h : a + b = 0)\r\n  : a = -b :=\r\nby\r\n  have h1 : (a + b) + -b = 0 + -b := by rw [h]\r\n  have h2 : (a + b) + -b = a := add_neg_cancel_right a b\r\n  have h3 : 0 + -b = -b := zero_add (-b)\r\n  rwa [h2, h3] at h1\r\n\r\n-- 4\u00aa demostraci\u00f3n\r\nexample\r\n  (h : a + b = 0)\r\n  : a = -b :=\r\nadd_eq_zero_iff_eq_neg.mp h\r\n<\/pre>\n<p><b>Demostraciones interactivas<\/b><\/p>\n<p>Se puede interactuar con las demostraciones anteriores en <a href=\"https:\/\/lean.math.hhu.de\/#url=https:\/\/raw.githubusercontent.com\/jaalonso\/Calculemus2\/main\/src\/Ig_opuesto_si_suma_ig_cero.lean\" rel=\"noopener noreferrer\" target=\"_blank\">Lean 4 Web<\/a>.<\/p>\n<p><b>Referencias<\/b><\/p>\n<ul>\n<li> J. Avigad y P. Massot. <a href=\"https:\/\/bit.ly\/3U4UjBk\">Mathematics in Lean<\/a>, p. 11.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Demostrar con Lean4 que si R es un anillo y a, b \u2208 R tales que a + b = 0 entonces a = -b Para ello, completar la siguiente teor\u00eda de Lean4: import Mathlib.Algebra.Ring.Defs import Mathlib.Tactic variable {R : Type _} [Ring R] variable {a b : R} example (h : a + b = 0) : a = -b := sorry<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_kad_post_transparent":"","_kad_post_title":"","_kad_post_layout":"","_kad_post_sidebar_id":"","_kad_post_content_style":"","_kad_post_vertical_padding":"","_kad_post_feature":"","_kad_post_feature_position":"","_kad_post_header":false,"_kad_post_footer":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[1],"tags":[284,297],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/1438"}],"collection":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/comments?post=1438"}],"version-history":[{"count":3,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/1438\/revisions"}],"predecessor-version":[{"id":1441,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/posts\/1438\/revisions\/1441"}],"wp:attachment":[{"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/media?parent=1438"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/categories?post=1438"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.glc.us.es\/~jalonso\/calculemus\/wp-json\/wp\/v2\/tags?post=1438"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}